Dilatacion Superficial Ejercicios Resueltos -

Af=A0⋅[1+β⋅ΔT]cap A sub f equals cap A sub 0 center dot open bracket 1 plus beta center dot cap delta cap T close bracket

Sabemos que $ΔT = T_f - T_i$, por lo tanto: dilatacion superficial ejercicios resueltos

Find the difference between the final and initial temperatures. : 3. Apply the Expansion Formula Substitute the known values into the equation to find the result. Af=A0⋅[1+β⋅ΔT]cap A sub f equals cap A sub

A0=π⋅d24=3,1416⋅(9 cm)24=3,1416⋅814≈63,617 cm2cap A sub 0 equals the fraction with numerator pi center dot d squared and denominator 4 end-fraction equals the fraction with numerator 3 comma 1416 center dot open paren 9 cm close paren squared and denominator 4 end-fraction equals the fraction with numerator 3 comma 1416 center dot 81 and denominator 4 end-fraction is approximately equal to 63 comma 617 cm squared dilatacion superficial ejercicios resueltos

[ A_f = A_0 (1 + \beta \Delta T) ]

β=2⋅(1.7×10-5 ∘C-1)=3.4×10-5 ∘C-1beta equals 2 center dot open paren 1.7 cross 10 to the negative 5 power raised to the composed with power C to the negative 1 power close paren equals 3.4 cross 10 to the negative 5 power raised to the composed with power C to the negative 1 power 2. Calcular la variación de temperatura