: If the developer fails to sanitize the input, an attacker can pass file:///etc/passwd (on Linux) or file:///C:/Windows/win.ini (on Windows) instead of a standard http:// link.
if response.status_code == 200: print(response.text) else: print('Failed to fetch URL') fetch-url-file-3A-2F-2F-2F
: When a URL like http://example.com is entered, the server makes a request, retrieves the HTML, and displays it back to the user. : If the developer fails to sanitize the
Thus, the most plausible interpretation is: the server makes a request
Verify that it decodes to fetch-url-file:/// . Use a simple tool:
fetch('http://example.com') .then(response => response.text()) .then(data => console.log(data)) .catch(error => console.error('Error:', error));